ok so I ams assuming that
from home to 1 is 60
from 1 to 2 is 60
from 2 to 3 is 60
from 3 to home is 60
so we have a squaer
from home to second base
that is a diagonal line through the square
find the distance
we see that we have 2 right triangles with legs 60 and 60
use pythagoren theorem to find hypotonuse (longest side)
a^2+b^2=c^2
60^2+60^2=c^2
3600+3600=c^2
7200=c^2
square root both sides
60√2=c
84.85=c
about 85 ft
