Respuesta :
[tex] 8\frac{3}{8}= \frac{67}{8} [/tex]
[tex] 2\frac{1}{2} = \frac{5}{2} = \frac{20}{8} [/tex]
[tex] \frac{67}{8}- \frac{20}{8} = \frac{47}{8} =5 \frac{7}{8} in[/tex]
[tex] 2\frac{1}{2} = \frac{5}{2} = \frac{20}{8} [/tex]
[tex] \frac{67}{8}- \frac{20}{8} = \frac{47}{8} =5 \frac{7}{8} in[/tex]
Answer: There is [tex]5\frac{7}{8}\ in.[/tex] left.
Step-by-step explanation:
Since we have given that
Length of ribbon Ramona had is given by
[tex]8\frac{3}{8}=\frac{67}{8}\ in.[/tex]
Length of ribbon she used for a project is given by
[tex]2\frac{1}{2}=\frac{5}{2}\ in.[/tex]
Number of inches of ribbon left is given by
[tex]\frac{67}{8}-\frac{5}{2}\\\\=\frac{67-20}{8}\\\\=\frac{47}{8}\ in\\\\=5\frac{7}{8}\ in.[/tex]
Hence, there is [tex]5\frac{7}{8}\ in.[/tex] left.