If there were a variable in both binomials, you would have to foil. However, since there isn't, you can simplify the second binomial and distribute it then:
[tex](2x+7)(2+3) \\ (2x+7)5 \\ 5(2x+7) \\ (5*2x)+(5*7) \\ 10x+35[/tex]
The answer is 10x+35.
Hope this helps!
