Question

for lunch britney has a choice of a hot dog, a hamburger, or pizza and a choice of an apple, a pear, or grapes. what are all the possible choices of lunch she can have? how many outcomes are in the sample space

Answer 1

Hot dog and apple
Hot dog and pear
Hot god and grapes
Hamburger and apple
Hamburger and pear
Hamburger and grapes
Pizza and apple
Pizza and pear
Pizza and grapes.

There are 9.

Answer 2

The correct answer is 9

What is permutation and combination?

• A permutation is an act of arranging the objects or numbers in order.
• Combinations are the way of selecting the objects or numbers from a group of objects or collection, in such a way that the order of the objects does not matter.

How to solve this problem?

The steps are as follow:

• We need to select any one from pizza , hamburger or hotdog = 3C1
• We need to select any one from pear , grapes or an apple = 3C1

Therefore the possibilities are 3C1*3C1 = 3!/1!(3-1)!*3!/1!(3-1)!

= 3*2!/1*2! *3*2!/1*2! = 3*3 = 9

Therefore , the number of possibilities is 9

Learn more about Permutation and combination here

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