What volume of ammonia in liters, at STP, can be produced from 2.0 kg of hydrogen gas, H2, and an excess of nitrogen gas, N2? N2 (g) + 3 H2 (g) → 2 NH3 (g)
N2 + 3H2 -> 2NH3 (Always check if it is balanced).
Ok so we have 2kg of hydrogen conver this to grams and then to moles. 2kg -> 2000g 2000g divide by R.M.M of H2 R.M.M 2H - 2 * 1 -> 2 2000/2 - 1000 moles. Look at the ratio of H2 to 2NH3. We see that we get 2NH3 for every H2 therefore the ratio is 1:2. This means that we HAVE 2000 moles of 2NH3. At stp. we know that 1 moles = 22.4 Litres We have 2000 moles that means that we produce 44800 litres of NH3 at stp. 2000 * 22.4 - 44800 Hope this helps :).
