Respuesta :
[tex]\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{7}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{7-5}{1-(-3)}\implies \cfrac{7-5}{1+3}\implies \cfrac{2}{4}\implies \cfrac{1}{2}[/tex]
Answer:
The slope the line that passes through the given points (-3, 5) and (1, 7) is 1/2. Hence first option is correct
Solution:
Given, two points are (-3, 5) and (1, 7)
We have to find the slope of a line that passes through the above given two points.
We know that, slope of a line that pass through [tex]\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)[/tex] is given by:
[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
Here, in our problem, [tex]x_{1}=-3, y_{1}=5 \text { and } x_{2}=1, y_{2}=7[/tex]
Now, slope m [tex]=\frac{7-5}{1-(-3)}=\frac{2}{1+3}=\frac{2}{4}=\frac{1}{2}[/tex]
Hence, the slope the line that passes through the given points is 1/2. So, first option is correct.
