Question

How much heat is required to raise the temperature of 65.8 grams of water from 31.5ºC to 46.9ºC? (The specific heat for water is 4.18 J/g·ºC)

Answer 1

q=(4.18/g' C) *(65.8g) * 4069'C- 31.5'C=4240

Answer 2

Answer:

4235.7J or 4.2KJ

Explanation:

The heat required to raise the temperature of water is given by

H= mcθ

Where

H= heat required= ?????

m= mass of the water body=65.8 grams

c= heat capacity of the water= 4.18 J/g·ºC

θ=temperature change= 46.9°C- 31.5°C= 15.4°C

H= 65.8 ×4.18 × 15.4= 4235.7J or 4.2KJ