Question

The population of a small town, P, as a function of time, t, in years past 1940 is given below.

P = 1,720 + 200t

For which of the following years was the population of the town 8,920?

Answer 1

Answer: 1976

Steps:

Let t* be the year in which the population reached a count of 8920. Solve for t*:

$P=200t+1720\\8920=200t^*+1720\\7200=200t^*\\t^* = 36$

The population grew to the number 8920 in 36 years past 1940, i.e., 1976

Answer 2

Answer:

1976

Step-by-step explanation:

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