Question

find the difference (x^3-7x+4x^2-2)-(2x^2-9x+4) = ?x^3+?x^2+?x+?

Answer 1

Answer:

=x3+2x2+2x−6

Step-by-step explanation:

x3−7x+4x2−2+−1(2x2−9x+4)

x3+−7x+4x2+−2+−1(2x2)+−1(−9x)+(−1)(4)

x3+−7x+4x2+−2+−2x2+9x+−4

x3+−7x+4x2+−2+−2x2+9x+−4

(x3)+(4x2+−2x2)+(−7x+9x)+(−2+−4)

x3+2x2+2x+−6