Answer: Our required integers will be 9,11,19.
Explanation:
Let three integers all less than 25 be x,y,z
Since we have given that
Range = 10
Mean = 13
These three integers will be
[tex]9,11,19[/tex]
Since their range is 10 i.e.
[tex]Range=Highest-Lowest=19-9=10[/tex]
And
Mean = 13
[tex]\frac{9+11+19}{3}=\frac{39}{3}=13[/tex]
So, it satisfies the above conditions and they are all less than 25.
Hence, our required integers will be 9,11,19.