Question

The area of rhombus is 35 square feet the length of one of the diagonals is 10 feet what is the length of the other diagonal

Answer 1

Area of a rhombus = $\frac{diagonalA*DiagonalB}{2}$

Given are:

Area = 35 square feet

Length of diagonal = 10 feet

Let the diagonal whose length is to be found be 'B'

So the length of the other diagonal =

$35=\frac{10*B}{2}$

$10B=70$

$B=7$

So, the length of the other diagonal is 7 feet.