As per Newton's II law we know that
[tex]F = \frac{dP}{dt}[/tex]
rate of change in momentum is Net outside force on the object
now here we will have if net outside force will be zero
then we can say
[tex]F = 0 = \frac{dP}{dt}[/tex]
so from above equation we can say
[tex]dP = 0[/tex]
and hence we have
[tex]P = constant[/tex]
so the correct answer will be
3.) in the absence of outside forces