Respuesta :

gmany

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have the points A(-5, 3) and B(3, -3). Substitute:

[tex]m=d\frac{-3-3}{3-(-5)}=\dfrac{-6}{8}=-\dfrac{3}{4}[/tex]

Answer: D) - 3/4

akposevictor

Using the slope formula,  [tex]\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}[/tex], the slope of the given line segment AB with endpoints A(-5, 3) and B(3, -3) is: [tex]\mathbf{D.-\frac{3}{4} }[/tex]

Using the slope formula, [tex]\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}[/tex], we can find the slope of the line segment AB.

  • Given the endpoints of segment AB:

A(-5, 3)

B(3, -3)

  • Let,

[tex]A(-5, 3) = (x_1, y_1)\\\\B(3, -3) = (x_2, y_2)[/tex]

  • Substitute each value into the slope formula to solve for m

[tex]m = \frac{-3 -3}{3 -(-5)} = \frac{-6}{8}[/tex]

  • Simplify further

[tex]\mathbf{m =-\frac{3}{4} }[/tex]

Therefore, using the slope formula,  [tex]\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}[/tex], the slope of the given line segment AB with endpoints A(-5, 3) and B(3, -3) is: [tex]\mathbf{D.-\frac{3}{4} }[/tex]

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