Question

identify the following conic section: 11x^2-3y^2- 88x+18y=116=0

Answer 1

11x^2-3y^2- 88x+18y=116

11x^2 -88x -3y^2 +18y = 116

11(x^2-8x)  -3(y^2+9y) =116

because of the subtraction of the y^2  we know it is a hyperbola