Respuesta :
Answer: The distance between the points (-6,7) and (-1,-5) is 13 units.
Solution:
P1=(-6,7)=(x1,y1)→x1=-6, y1=7
P2=(-1,-5)=(x2,y2)→x2=-1,y2=-5
Distance between points P1 and P2: d=?
d=sqrt [ (x2-x1)^2 + (y2-y1)^2 ]
Replacing the knwon values:
d=sqrt [ (-1-(-6))^2 + (-5-7)^2 ]
d=sqrt [ (-1+6)^2 + (-12)^2 ]
d=sqrt [ (5)^2 + 144 ]
d=sqrt [ 25 + 144 ]
d=sqrt [ 169 ]
d=13
You need to use the distance formula [tex]\sqrt{(x2-x1)^2} +(y2-y1)^2\\[/tex]
Then you'll use the slope intercept distance formula and substitute (-6,7) (-1,-5)
When you do you'll solve the problem and get an answer of a distance between the two points of 13.