Question

The baseball diamond is really a square. The distance between each of the bases is 90 feet. How far does the catcher have to throw the ball to get from home plate to second base? Round your answer to the nearest foot. A) 90 feet B) 100 feet C) 127 feet D) 156 feet

Answer 1

a^2 + b^2 = c^2

base lines: home to first is a, first to second is b, home to second is c.

90^2 + 90^2 = c^2
or
$\sqrt{ {90}^{2} + {90}^{2} } = c$
$c = 127.28$
...approximately

Answer 2

If the baseball diamond is really a square. The distance between each of the bases is 90 feet. How far does the catcher have to throw the ball to get from home plate to second base will be:  C) 127 feet

How far does the catcher have to throw the ball to get from home plate to second base will be calculated as:

Total distance covered=√(90ft)²+(90ft)²

Total distance covered=√8,100ft +8,100ft

Total distance covered=√16,200ft²

Total distance covered=127 feet

Inconclusion if the baseball diamond is really a square. The distance between each of the bases is 90 feet. How far does the catcher have to throw the ball to get from home plate to second base will be:  C) 127 feet

Learn more here:

https://brainly.com/question/4198390