So firstly, we need to factor out the GCF. Since all the terms share a GCF of x, factor that out as such:
[tex](x)(x^2y^2-x^4+y^3-yx^2)[/tex]
Next, I will be factoring by grouping. For this, factor x²y² + y³ and -x⁴ - yx². Make sure that they have the same quantity on the inside:
[tex](x)(y^2(x^2+y)-x^2(x^2+y))[/tex]
Now rewrite the expression as:
[tex](x)(y^2-x^2)(x^2+y)[/tex]
However, we can factor this expression further. Next, we will be applying the difference of squares rule, which is [tex]x^2-y^2=(x+y)(x-y)[/tex] . In this case:
[tex]y^2-x^2=(y+x)(y-x)\\\\(x)(y+x)(y-x)(x^2+y)[/tex]
In short, the factored form of this expression is:
[tex](x)(y+x)(y-x)(x^2+y)[/tex]