Question

In the resonance structure with the electron geometry "c tetrahedral; 1st n trigonal planar; 2nd n linear" would you expect the two nitrogen-nitrogen bond angles and bond lengths to be the same or different?

Answer 1

Hey there!:

*Since 1st N is trigonaplanar which indicates sp2 hybridized N and bond angle will be 120º  .

*Thus C-N-N bond angle is 120º  .

*Since 2nd N is said to have linear we get N-N-N  bond angle 180º .

Now as we have resonance both N1-N2 and N2-N3  will have equal lengths .

Hope that helps!

Answer 2

Answer:

• The 1st n trigonal planar will be sp2 hybridized and the bond angle will be equal to 120°.

• There for the angle between Carbon-Nitrogen-Nitrogen bond is 120°.

• The 2nd n is linear which means that we will get 180° bond angle for n-n-n and as we have resonance that will make bond length for n1-n2 and n2-n3 equal.