By De Broglie concept of dual nature of light we know that
[tex]\lambda = \frac{h}{mv}[/tex]
here we know that for this validity the wavelength must be equal to the diameter of the molecule
so here we have
[tex]\lambda = 8.80 nm[/tex]
now from above equation
[tex]8.80* 10^{-9} = \frac{6.6 * 10^{-34}}{9.1*10^{-31}*v}[/tex]
[tex]v = \frac{6.6 * 10^{-34}}{9.1 * 10^{-31} * 8.80 * 10^{-9}}[/tex]
[tex]v = 8.24 * 10^4 m/s[/tex]
Now the kinetic energy of the electron is given as
[tex]KE = \frac{1}{2}mv^2[/tex]
[tex]KE = \frac{1}{2}*9.1*10^{-31}*(8.24* 10^4)^2[/tex]
[tex]KE = 3.1 * 10^{-21} J[/tex]
so above is the KE of electron