Question

If sine of x equals square root of 2 over 2, what is cos(x) and tan(x)? Explain your steps in complete sentences.

Answer 1

sin$x$=$\frac{opposite}{hypotenuse}$ =$\frac{ \sqrt{2} }{2}$
     opposite=$\sqrt{2}$
     hypotenuse=2

$Adjacent^{2}$+$(\sqrt{2 })^{2 }$= $2 ^{2}$
$Adjacent^{2}$+2=4
$Adjacent^{2}$=2 
Adjacent=$\sqrt{2}$

cos$x$=$\frac{ajc}{hyp}= \frac{ \sqrt{2} }{2}$
Tan$x$=$\frac{opp}{adj} = \frac{ \sqrt{2} }{ \sqrt{2} }$