what is the slope intercept form of the linear equation with a graph that passes through (-2,2) and is perpendicular to the graph of y=1/3x+9

Respuesta :

sid071

Hey there!!

Steps to get into equation which is perpendicular:

  • Change the slope
  1. The slope of a perpendicular line is always negative reciprocal.
  • Take the point and get that into point-slope form.
  1. y - y = m ( x - x )
  • Convert this equation into slope-intercept form.

'm' is the slope.

We have the slope as 1/3

The perpendicular slope would be -3.

Point slope:

The point = (-2,2)

y - 2 = -3( x - (-2) )

y - 2 = -3(x+2)

y - 2 = -3x -6

Adding 2 on both sides:

y = -3x - 4

Hence, the equation would be :

y = -3x - 4

Hope it helps!