Question

Joaquin has hockey practice at the same ice rink where Alton has curling practice. One day, they were both playing on the ice with their equipment. They noticed two crashes in particular: In Crash 1, Alton’s curling stone with more mass was moving along and crashed into Joaquin's hockey puck. In Crash 2, Alton's curling stone with less mass was moving along and crashed into Joaquin's hockey puck. It was the same hockey puck with the same mass in both crashes. Joaquin and Alton want to know about the motion of the hockey puck after the crashes. Why would the crash affect the hockey puck, and which crash would cause a greater change in motion for the hockey puck?

Answer 1

Answer:

The correct answer is the greater the mass, the greater the force. The hockey puck will move a greater distance in crash 1 than in crash 2.

Explanation:

The force with which a body moves depends on the acceleration it has and its mass. Since the bodies are solid, inelastic shocks are produced, in which all the energy is transmitted from one body to another. In case 1, the impacting body has a greater mass, producing a greater force on the hockey puck, causing it to travel a greater distance. In the second case, being massless, there will be a crash where the body that impacts will be still and the hockey puck will move less than in case 1.

Have a nice day!

Answer 2

According to the law of conservation momentum, the total momentum in a closed system is constant

• The crash would affect the puck because, the curling stone is much larger than the hockey puck

• The crash by the larger mass curling stone will cause a greater change in motion for the hockey puck

The reasons the above effects are correct are;

The given information are;

The sport being engaged in:

• Joaquin; Hockey

• Alton; Curling

The crashes observed;

Crash 1; The larger mass curling stone crashed into the hockey puck

Crash 2; The lesser mass curling stone crashed into the hockey puck

The mass of the hockey puck in both crashes = $m_{hockey}$

The mass of the larger mass curling stone = M

The mass of the smaller mass curling stone = m

According to the law of conservation of momentum, and assuming that the curling stone and the hockey puck move together after the collision, we have;

Larger mass curling stone

M×v₁ - $m_{hockey}$×v₂ = (M -

Lesser mass curling stone

m×v₁ - $m_{hockey}$×v₂ = (m -

Given that M > m, and $m_{hockey}$ is constant, we have;

(M - $m_{hockey}$) >  (m -

According to the above equations, the momentum given to the hockey puck by the large curling stone is more than that given by the lesser mass curling stone

Therefore,

The crash by the larger mass curling stone will cause a greater change in motion for the hockey puck

the crash would affect the puck because, the curling stone is much larger than the puck

Learn more about conservation of linear momentum here:

https://brainly.com/question/24159955

https://brainly.com/question/24424291

https://brainly.com/question/22698801