Question

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)

Answer 1

For this case we have the following functions:
 $f (x) = 4 - x ^ 2 g (x) = 6x$
 The first thing we must do is subtract both functions.
 We have then:
 $(g - f) (x) = g (x) - f (x)$
 Substituting values we have:
 $(g - f) (x) = (6x) - (4 - x ^ 2)$
 Rewriting we have:
 $(g - f) (x) = x ^ 2 + 6x - 4$
 Then, we evaluate the function for x = 3.
 We have then:
 $(g - f) (3) = 3 ^ 2 + 6 (3) - 4$
 Rewriting:
 $(g - f) (3) = 9 + 18 - 4 (g - f) (3) = 23$
 Answer:
 An expression that is equivalent to (g - f) (3) is:
 $(g - f) (3) = 23$

Answer 2

Answer:

$(g-f)(3)=23$

Step-by-step explanation:

Given : $f(x) = 4 -x^2$ and $g(x) = 6x$

To find : The value of $(g -f)(3)$

Solution :

First we find the value of (g-f)

$(g-f)(x)= g(x)-f(x)$

$(g-f)(x)=6x-(4-x^2)$

$(g-f)(x)=6x-4+x^2$

Now, put the value of x=3

$(g-f)(3)=6(3)-4+(3)^2$

$(g-f)(3)=18-4+9$

$(g-f)(3)=23$

Therefore, $(g-f)(3)=23$