Question

Solve for xxx. Write the smaller solution first, and the larger solution second.
x^2 + 3x - 10 = 0x
2
+3x−10=0x, start superscript, 2, end superscript, plus, 3, x, minus, 10, equals, 0
\text{smaller }x = smaller x=s, m, a, l, l, e, r, space, x, equals

\text{larger } x = larger x=l, a, r, g, e, r, space, x, equals

Answer 1

Answer:

$x=-5\text{ or }x=2$

Step-by-step explanation:

We have been given an equation $x^2+3x-10=0$. We are asked to find the solutions of our given equation.

We will use splitting the middle term method to solve quadratic equation.

We will split middle term of our given equation into parts such that whose product is $-10$ and whose sum is 3.

We know that such two numbers are $5\text{ and }-2$.

$x^2+5x-2x-10=0$

$(x^2+5x)+(-2x-10)=0$

$x(x+5)-2(x+5)=0$

$(x+5)(x-2)=0$

Using zero product property, we will get:

$(x+5)=0\text{ or }(x-2)=0$

$x+5=0\text{ or }x-2=0$

$x=-5\text{ or }x=2$

Therefore, the solutions for our given equation are $x=-5\text{ or }x=2$.