Given:
a1(first term in arithmetic sequence): 14
a25 ( 25th term in arithmetic sequence): 206
Let d be the arithmetic difference
a25= a1+ 24d
206= 14+ 24 x d
Solving for d we get
d=8.
Thus the arithmetic difference is 8.
Answer:
The common difference is 8
Explanation:
The first term of an arithmetic progression is 14 and the 25th term is 206. The formula to calculate for arithmetic progression is as follows:
Ap = a + (n-1)d
where
a = first term
n = number of term
d = common difference
a = 14
n = 25
Ap = 206
d = ?
The 25th term is 206 ,therefore,
206 = 14 + ( 25 - 1 ) d
206 = 14 + (24)d
collect like terms
206 - 14 = 24d
192 = 24d
divide both sides by 24
d = 192/24
d = 8
The common difference is 8
