Answer:
Distance between their seats is 4√2 units.
Step-by-step explanation:
We are given that James mapped his seat and teacher's seat at (0,10) and (-4,6) on the coordinate plane.
So, distance between their seats= distance between the points (0,10) and (-4,6)
=[tex]\sqrt{(-4-0)^{2}+(6-10)^{2}}[/tex]
=[tex]\sqrt{(-4)^{2}+(-4)^{2}}=\sqrt{16+16}[/tex]
[tex]=\sqrt{32}=4\sqrt{2}units[/tex]