Question

Abigail has 2 and 1/7th cakes. She dropped 1 2/5th of the cakes. How much cake does she have left.

Answer 1

Abigail has 2 and 1/7th cakes. She dropped 1 2/5th of the cakes

Abigail has  $2\frac{1}{7} = \frac{15}{7}$ cakes

She dropped  $1 \frac{2}{5} = \frac{7}{5}$ of the cakes

To find the amount of cake left, we subtract the amount of cake dropped from the whole cake

Cake left = $\frac{15}{7} - \frac{7}{5}$

To subtract fractions make the denominators same

LCD is 7* 5 = 35

$\frac{15*5}{7*5} - \frac{7*7}{5*7}$

$\frac{75}{35} - \frac{49}{35}$

$\frac{75 - 49}{35}$

$\frac{26}{35}$

$\frac{26}{35}$ of cake she have left

Answer 2

Answer:

$\frac{26}{35} th$ of the cake.

Step-by-step explanation:

Abigail has $2\frac{1}{7} th$ cakes and she drops $1\frac{2}{5}$ of it.

To find out how much cake she is left with now, we just need to subtract the amount of cake she dropped from the amount of cake she had initially.

$2\frac{1}{7} - 1\frac{2}{5}$

Change these mixed fractions to improper fractions:

$\frac{15}{7} -\frac{7}{5}$

Taking the LCM to get:

$\frac{(15*5)*(7*7)}{35} = \frac{75-49}{35} =\frac{26}{35}$

Therefore, Abigail is now left with 26/35th of the cake.