Question

The reaction for the burning of one type of match tip is as follows: P4S3(s) + 8 O2(g) P4O10(g) + 3 SO2(g) What volume of SO2 at STP can be produced by burning 1.00 g P4S3 in excess O2?

Answer 1

a] work out mass of 1 mole P4S3 -- call this Y grams

b] eqtn tells you 1 mole P4S3 gives 3 moles SO2 [= 3 x 22.4L at STP]  

c] by simple proportion  

1g P4S3 gives (3 x 22.4)/Y SO2 at STP answer