Martha squeezes 5 oranges to make juice. If she already has 3/5 liters of juice, how many times does she need to fill a container that has 9/10 capacity?
According to the problem, with 5 oranges Martha has [tex]\frac{3}{5}[/tex] litters of orange juice.
First we have to find how many litters are needed to reach the [tex]\frac{9}{10}[/tex] litters capacity of the container. This can be mathematically expressed as follows:
[tex]\frac{3}{5}L+X=\frac{9}{10}L[/tex]
Let’s find X:
[tex]X=\frac{9}{10}L-\frac{3}{5}L[/tex]
[tex]X=\frac{3}{10}L[/tex]
This means that Martha needs [tex]\frac{3}{10}L[/tex] to reach the [tex]\frac{9}{10}L[/tex] capacity.
Now, if 5 oranges represent [tex]\frac{3}{5}L[/tex], how many oranges represent [tex]\frac{3}{10}L[/tex]?
This can be solved by “the rule of three” also called cross-multiplication:
5 oranges--------[tex]\frac{3}{5}L[/tex]
N oranges--------[tex]\frac{3}{10}L[/tex]
[tex]N=\frac{\frac{3}{10}L(5)}{\frac{3}{5}L}[/tex]
[tex]N=\frac{5}{2}oranges[/tex]
This is equivalent to [tex]2.5 oranges[/tex]
This means Martha needs 2.5 oranges or [tex]\frac{3}{10}L[/tex] to to fill a container that has 9/10 capacity.