(Let x = greater number and y = lesser number)
So this question is asking us for a system of equations. Using the info they provide, we can form these two equations:
[tex]x=y+7\ \textsf{("The greater of the numbers is 7 more than the lesser.")}\\3x=4y+5\ \textsf{("Three times the greater number is 5 more than 4 times the lesser number.")}[/tex]
So for this, we will be using the substitution method. Since we know that x = y + 7, substitute x with (y + 7) in the second equation as such:
[tex]3(y+7)=4y+5[/tex]
From here we can solve for y. Firstly, distribute 3 so that it multiplies with y and 7:
[tex]3y+21=4y+5[/tex]
Next, subtract 3y on both sides of the equation:
[tex]21=y+5[/tex]
Lastly, subtract 5 on both sides of the equation:
[tex]16=y[/tex]
Now that we know the value of y, we can substitute it into either equation to solve for x:
[tex]x=16+7\\x=23\\\\3x=4(16)+5\\3x=64+5\\3x=69\\x=23[/tex]
In short, 16 is the lesser number and 23 is the greater number.