For this question we have to take LCM of the fractions to simplify it and process further. So, by LaTeX interpreter equation editor, Here we go.
[tex]\mathbf{Least \: Common \: Multiplier: 3x}[/tex]
[tex]\mathbf{\dfrac{2}{x} \times 3x + \dfrac{1}{3} \times 3x - \dfrac{4}{x} \times 3x}[/tex]
Combine the fractions to multiply the numerator.
[tex]\mathbf{\dfrac{2 \times 3x}{x} + \dfrac{1 \times 3}{3}x = \dfrac{4 \times 3x}{x}}[/tex]
[tex]\mathbf{\dfrac{6x}{x} + \dfrac{3}{3}x = \dfrac{12x}{x}}[/tex]
[tex]\mathbf{6 + x = 12}[/tex]
Just subtract both of the current sides by the numbered value "6".
[tex]\mathbf{6 + x - 6 = 12 - 6}[/tex]
[tex]\boxed{\underline{\mathbf{Final \: \: Answer: \: x = 6}}}[/tex]
Hope it helps.
