There are two ways to execute this equational expression. One is without the use of distributive law, which is going to be a long process given, we are not skipping the middle steps and solving it fully. Second one is about using distributive law. Both the methods will yield the same answer as a fully distributed expression. So, here is my process via LaTeX, the equation editor to interpret mathematical expressions.
Method 1: Without the use of distributive law.
Just apply the FOIL method which is given by the rule of expanding the brackets.
[tex]\boxed{\mathbf{FOIL \: Rule: \: (a + b) (c + d) = ac + ad - bc + bd}}[/tex]
[tex]\mathbf{x \times 2x + x (- 1) + 3 \times 2x + 3 (- 1) \big(- 2x + 1 \big)}[/tex]
[tex]\mathbf{2xx - 1 \times x + 3 \times 2x - 3 \times 1 \big(- 2x + 1 \big)}[/tex]
[tex]\mathbf{\big(2x^2 - x + 6x - 3 \big) \big(- 2x + 1 \big)}[/tex]
[tex]\mathbf{\big(2x^2 - 5x - 3 \big) \big(- 2x + 1 \big)}[/tex]
[tex]\mathbf{2x^2 (- 2x) + 2x^2 \times 1 + 5x (- 2x) + 5x \times 1 + (- 3) (- 2) + (- 3) \times 1}[/tex]
[tex]\mathbf{- 2 \times 2x^2x + 2 \times 1 \times x^2 - 5 \times 2xx + 5 \times 1 \times x + 3 \times 2x - 3 \times 1}[/tex]
[tex]\mathbf{- 4x^3 + 2x^2 - 10x^2 + 5x + 6x - 3}[/tex]
[tex]\mathbf{- 4x^3 + 2x^2 - 10x^2 + 11x - 3}[/tex]
[tex]\boxed{\mathbf{\underline{Final \: \: Answer: - 4x^3 - 8x^2 + 11x - 3}}}[/tex]
The second method relies on variable values equalling to the numbered values, it is a little more longer process than the former one. I advise you to stick to this method for now as a distribution for the bracketed expressions.
Hope it helps.
