Question

deanna and lise are playing games at the arcade. Deanna started with 15$ , and the macbine she is playing cost 0.75$ per game. Lose started with 13$, and her machine costs $0.50 per game. After how many games will the two girls have the same amount of money remaining?

Answer 1

Answer:

At 8 games, the girls will have the same ammount of money remaining.

Step-by-step explanation:

So we want to know at what time does these equations become the same. We simply write a equality like this:

$15-.75x=$13-.50x

We want to move the x over to the other side of the equation by simply doing this:

-.75x+.50x=13-15 --> Remember that this is a positive .50 because we did the opposite

Simplify

-.25x=-2 --> Remember that two negatives make a positive

x=8

Answer 2

After 8 games, the two girls have the same amount of money remaining.

The equation of a straight line is given by:

y = mx + b;

where y,x are variables, m is the slope of the line and b is the y intercept.

let x represent the number of games and y represent the money remaining after x games.

For scenario 1, Deanna started with 15$ , and the machine she is playing cost 0.75$ per game. The linear equation becomes:

y = -0.75x + 15

For scenario 2, Lose started with 13$, and her machine costs $0.50 per game. The linear equation becomes:

y = -0.5x + 13

For the two girls to have the same amount remaining:

-0.75x + 15 = -0.5x + 13

0.25x = 2

x = 8 games

Therefore after 8 games, the two girls have the same amount of money remaining.

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