Answer : D
[tex]\frac{3t^2-4t+1}{t+3} - \frac{t^2+2t+2}{t+3}[/tex]
The denominators are same
So we combine the numerators
[tex]\frac{(3t^2-4t+1)-(t^2+2t+2)}{t+3}[/tex]
To remove parenthesis we distribute negative sign inside the second parenthesis
[tex]\frac{3t^2-4t+1-t^2-2t-2)}{t+3}[/tex]
[tex]\frac{3t^2-4t+1-t^2-2t-2)}{t+3}[/tex]
[tex]\frac{2t^2-6t-1)}{t+3}[/tex]
Morgan made a mistake. He forgot to distribute the negative sign
Morgan forgot to distribute the negative sign to two of the terms 2t and 2 inside second parenthesis
