please help and tell me how to do so!

[tex]75 <\dfrac{x-2}{3} < 76\qquad|\text{multiply both sides by }\ \dfrac{1}{2}\ \text{(divide by 2)}\\\\\dfrac{1}{2}\cdot75 < \dfrac{1}{2}\cdot\dfrac{x-2}{3} < \dfrac{1}{2}\cdot76\\\\37.5 < \dfrac{x-2}{6} < 38\\\\Answer:\ C.\ 37\dfrac{2}{3}\ \text{because}\ 37.5 < 37\dfrac{2}{3}=37.\overline{6} < 38[/tex]