Question

What is the width of a rectangle with an area of 5/8 in 2 and a length of 10 inches?

Answer 1

The formula for area is: Area = Length x width.

We are given the area and length:

Area = 5/8 in^2

Length = 10 inches:

Replace the given values into the formula:

5/8 in^2 = 10 x width

To find the width, divide both sides by 10:

Width = 5/8 / 10

Width = 1/16 inch

Answer 2

Answer:  The required width of the given rectangle is $\dfrac{1}{16}~\textup{inches}.$

Step-by-step explanation:  We are given to find the width of a rectangle with an area of $\dfrac{5}{8}~\textup{in}^2$ and a length of 10 inches.

Let w inches represents the width of the given rectangle.

Then, we must have

$w\times10=\dfrac{5}{8}\\\\\\\Rightarrow w=\dfrac{1}{10}\times\dfrac{5}{8}\\\\\\\Rightarrow w=\dfrac{1}{16}.$

Thus, the required width of the given rectangle is $\dfrac{1}{16}~\textup{inches}.$