Find the value of x so that the figures have the same perimeter... #9

A , x = 4
The perimeter of the triangle = 5x + 1 +2x + 5 + 3x + 4 = 10x + 10
The perimeter of the rectangle = 2x + 2x + x + 13 + x + 13 = 6x + 26
Equating the 2 perimeter expressions
10x + 10 = 6x + 26 ( subtract 6x from both sides )
4x + 10 = 26 ( subtract 10 from both sides )
4x = 16 ( divide both sides by 4 )
x = 4 → A
The perimeter of a shape is the sum of side lengths of the shape.
The value of x so that they have the same perimeter is 4
The perimeter of the triangle is calculated as follows:
[tex]P_1 = 3x + 4 + 5x + 1 + 2x + 5[/tex]
Collect like terms
[tex]P_1 = 3x + 5x + 2x+ 4 + 1 + 5[/tex]
[tex]P_1=10x + 10[/tex]
The perimeter of the rectangle is calculated as follows:
[tex]P_2 = 2 \times (2x + x + 13)[/tex]
[tex]P_2 = 2 \times (3x + 13)[/tex]
Open brackets
[tex]P_2 = 6x + 26[/tex]
When they have the same perimeter;
[tex]P_1= P_2[/tex]
So, we have:
[tex]10x + 10 = 6x + 26[/tex]
Collect like terms
[tex]10x - 6x = 26 - 10[/tex]
[tex]4x = 16[/tex]
Divide by 4
[tex]x = 4[/tex]
Hence, the value of x is 4
Read more about perimeters at:
https://brainly.com/question/6465134