Given that the owner of a baseball stadium found that he sells an average of 586 tickets to each game when he charges an average of $59 per ticket.
So number of tickets = 586
Profit on 1 ticket = $59
Say price is increased once then new cost of ticket = 59+6
Say price is increased twice then new cost of ticket = 59+6*2
Say price is increased thrice then new cost of ticket = 59+6*3
In the same pattern
Say price is increased x-times then new cost of ticket = 59+6*x
In same pattern number of tickets sold will decrease by multiple of 4
Hence number of tickets sold when cost is increased x-times = 586-4*x
Then profit when cost is increased x-times = (586-4*x) (59+6*x)
Let P(x) represents profit when price is increased x-times then the required function will be:
P(x)= (586-4x)(59+6x)
Hence final answer will be choice matching with P(x)= (586-4x)(59+6x)