Question

an airplane accelerates down a runway at 3.20 m/s for 32.8 s until it finally lifts off the ground. determined the distance traveled before take off

Answer 1

Initial velocity is - 0 m /s.

Acceleration is - 3.20 m / s^2

Time - 32.8 s

According to the laws of motion.

S = ut + 1/2 at ^2

S = 1/2 at²

S = 1/2(3.20)(32.8)²

S = 1721.344 m

So the distance traveled before takeoff is 1731.3m