22katelynfrankouqqrb
22katelynfrankouqqrb 22katelynfrankouqqrb
  • 30-10-2018
  • Mathematics
contestada

3.) -3y ≤ –18

a. y ≤ –6
b. y ≤ 6
c. y ≥ 6
d. y ≥ 54

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devin258
devin258 devin258
  • 30-10-2018
The answer would be C
[tex] - 3y \leqslant - 18 \\ \\ y \geqslant \frac{ - 18}{ - 3} \\ \\ y \leqslant 6[/tex]
When you multiply by the negative number, switch the inequality
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