Question

A quarterback throws a football toward a receiver from a height of 6 ft. The initial vertical velocity of the ball is 14 ft/s. At the same time that the ball is thrown, the receiver raises his hands to a height of 8 ft and jumps up with an initial vertical velocity of 10 ft/s. Projectile motion formula: h = -16t2 + vt + h0 t = time, in seconds, since the ball was thrown h = height, in feet, above the ground { complete the system that models the heights of the ball and the receiver's hands over time.

Answer 1

Answer:

6,10,8

Step-by-step explanation:

h = -16t2 + vt + h0

t = time, in seconds, since the ball was thrown

h = height, in feet, above the ground

h = -16t² + 14t +

h = -16t² +

t

+

Answer 2

Answer:

Given the projectile formula:

$h = -16t^2+vt+h_0$

where, t is the time in second.

As per the statement:

A quarterback throws a football toward a receiver from a height of 6 ft. The initial vertical velocity of the ball is 14 ft/s

⇒$h_0 = 6 ft$ and v= 14 ft/s

Substitute these given values we have;

$h = -16t^2+14t+6$

It is also given that at the same time that the ball is thrown, the receiver raises his hands to a height of 8 ft and jumps up with an initial vertical velocity of 10 ft/s.

⇒$h_0 = 8 ft$ and v= 10 ft/s

then;

$h = -16t^2+10t+8$

Therefore, the system that models the heights of the ball and the receiver's hands over time :

$h = -16t^2+14t+6$

$h = -16t^2+10t+8$