Given:
Excited state electron configuration of H atom = 3s¹
To determine:
Energy of the electron in this state
Explanation:
The energy 'E' of an electron in a hydrogen atom occupying a level, 'n' is given by the formula:
En = -E₀/n²
where, E₀ is the ground state energy = 13.6 eV
n = principle quantum number i.e. n = 1,2,3...
Therefore,
En = -13.6/n² eV
In this case for a 3s¹ configuration, n = 3
E = -13.6/(3)² = -1.51 eV
Ans: Energy of the electron in a 3s1 state is -1.51 eV
