[tex]A.\\f(x)=2x-4\to y=2x-4\\\\\text{change x to y and y to x}\\\\x=2y-4\\\\\text{solve for y}\\\\2y-4=x\qquad|+4\\\\2y=x+4\qquad|:2\\\\y=\dfrac{1}{2}x+2\\\\f^{-1}(x)=g(x)=\dfrac{1}{2}x+2\\B.\\\text{Verifying if two functions are inverses of each other is a simple two-step process.}\\1.\ \text{Plug}\ f(x)\ \text{into}\ g(x)\ \text{and simplify}\\2.\ \text{Plug}\ g(x)\ \text{into}\ f(x)\ \text{and simplify}\\\\If\ g[f(x)]=f[g(x)]=x,\ then\ functions\ are\ inverses\ of\ each\\\ other.[/tex]
[tex]f(x)=2x-4,\ g(x)=\dfrac{1}{2}x+2\\\\g[f(x)]=\dfrac{1}{2}(2x-4)+2=\dfrac{1}{2}(2x)+\dfrac{1}{2}(-4)+2=x-2+2=x\\\\f[g(x)]=2\left(\dfrac{1}{2}x+2\right)-4=2\left(\dfrac{1}{2}x\right)+2(2)-4=x+4-4=x\\\\\text{Since the results above came out OK, both}\ x,\text{ then we can claim}\\\text{that functions f (x) and g (x) are inverses of each other.}[/tex]
