Question

How do you simplify this problem

Answer 1

3x^-3y^2z^-1 is the simplification.

Answer 2

$\frac{6 {x}^{ - 2} {y}^{3} {z}^{ - 1}}{2xy} = \frac{2xy( 3{x}^{ - 3} {y}^{2} {z}^{ - 1} ) }{2xy}$
$= 3 {x}^{ - 3} {y}^{2} {z}^{ - 1}$