Use synthetic division to determine which of the following are the real zeroes of the function f(x) = 3x^3 + 10x^2 + 4x - 8

Answer : option B
[tex]f(x) = 3x^3 + 10x^2 + 4x - 8[/tex]
We have -2 in the given option
Lets use synthetic division and divide by -2
First write the coefficient of all the terms in f(x)
-2 3 10 4 -8
0 -6 -8 8
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3 4 -4 0
We got remainder =0 , so -2 is one of the zero
Resultant expression is 3x^2 + 4x -4
Lets use synthetic division and divide by -2 again
-2 3 4 -4
0 -6 4
------------------------------------------------------
3 -2 0
We got remainder =0 , so -2 is again a zero
Resultant expression is 3x - 2
we set 3x -2 =0
Add 2 on both sides
3x = 2
Divide by 3 on both sides
[tex]x = \frac{2}{3}[/tex]
So zeros are [tex]-2, \frac{2}{3}[/tex]
Answer:
option b is correct
Step-by-step explanation:
In the options a, c and d we have to check if 2 is a root.
The coefficients of f(x) = 3x^3 + 10x^2 + 4x - 8 are: 3, 10, 4 and -8.
The division of f(x) by (x-2) using synthetic division is:
2 3 10 4 -8
6 32 72
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3 16 36 64
The remainder is 64, so 2 is not root of f(x); if it was the remainder would be zero. This result makes options a, c and d incorrect.
The division of f(x) by (x+2) using synthetic division is:
-2 3 10 4 -8
-6 -8 8
------------------------------------------------------
3 4 -4 0
The remainder is 0, so -2 is root of f(x).
The division of f(x) by (x-2/3) using synthetic division is:
2/3 3 10 4 -8
2 8 8
------------------------------------------------------
3 12 12 0
The remainder is 0, so 2/3 is root of f(x). Then, option b is correct