Find the area of the polygon. show your work

Look at the picture.
We have the triangle and the parallelogram.
The formula of an area of a triangle
[tex]A_T=\dfrac{bh}{2}[/tex]
We have b = 5 and h = 3. Substitute:
[tex]A_T=\dfrac{5\cdot3}{2}=\dfrac{15}{2}=7.5[/tex]
The fromula of an area of a parallelogram:
[tex]A_P=bh[/tex]
We have b = 5 and h = 3. Substitute:
[tex]A_P=5\cdot3=15[/tex]
The area of polygon:
[tex]A=A_T+A_P\to A=7.5+15=22.5\ u^2[/tex]
--------------------------------------------------
Other method. (look at the second picture).
We have the three congruent triangles. The area of the polygon is equal three times the area of a one triangle.
[tex]A_\Delta=\dfrac{bh}{2}[/tex]
b = 5, h = 3. Subsitute.
[tex]A_\Delta=\dfrac{5\cdot3}{2}=\dfrac{15}{2}=7.5[/tex]
The area of the polygon:
[tex]A=3A_\Delta\to A=3\cdot7.5=22.5\ u^2[/tex]