Please help me
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ANSWER TO PART A
The given triangle has vertices [tex]J(-4,1), K(-4,-2),L(-3,-1)[/tex]
The mapping for rotation through [tex]90\degree[/tex] counterclockwise has the mapping
[tex](x,y)\rightarrow (-y,x)[/tex]
Therefore
[tex]J(-4,1)\rightarrow J'(-1,-4)[/tex]
[tex]K(-4,-2)\rightarrow K'(2,-4)[/tex]
[tex]L(-3,-1)\rightarrow L'(1,-3)[/tex]
We plot all this point and connect them with straight lines.
ANSWER TO PART B
For a reflection across the y-axis we negate the x coordinates.
The mapping is
[tex](x,y)\rightarrow (-x,y)[/tex]
Therefore
[tex]J(-4,1)\rightarrow J''(4,1)[/tex]
[tex]K(-4,-2)\rightarrow K''(4,-2)[/tex]
[tex]L(-3,-1)\rightarrow L''(3,-1)[/tex]
We plot all this point and connect them with straight lines.
See graph in attachment