2x + 3 < 19 and 2x − 3 ≤ -7
Solve each inequality
2x + 3 < 19
subtract 3 from both sides
2x < 16
Divide both sides by 2
x < 8
2x − 3 ≤ -7
Add 3 on both sides
2x ≤ -4
Divide both sides by 2
x ≤ -2
we got x<8 and x ≤ -2
When we combine both solutions then we will get
x ≤ -2
Interval form is (-infinity, -2]