(1)
we are given
[tex]\frac{q^2-7q-8}{q^2+3q-4}[/tex]
We know that any function is undefined when denominator =0
so, we will set denominator =0
and then we can solve for q
[tex]q^2+3q-4=0[/tex]
now, we can factor it
[tex](q+4)(q-1)=0[/tex]
[tex](q+4)=0[/tex]
[tex]q=-4[/tex]
[tex](q-1)=0[/tex]
[tex]q=1[/tex]
so,
q≠1 and q≠−4............Answer
(2)
we are given
[tex]\frac{y^2-3y-40}{y^2+9y+20}[/tex]
Since, any function is undefined when denominator =0
so, we set denominator =0
and then we can solve for y
[tex]y^2+9y+20=0[/tex]
[tex](y+4)(y+5)=0[/tex]
[tex](y+4)=0[/tex]
[tex]y=-4[/tex]
[tex](y+5)=0[/tex]
[tex]y=-5[/tex]
so,
y≠−5
y≠−4.............Answer
Answer:
1: q ≠ 1 and q ≠ -8
2: -4 and -5
Step-by-step explanation:
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