Respuesta :
[tex]6x - 2 = - 4x + 2 \\ 6x - 2 + 4x = - 4x + 2 + 4x \\ 10x - 2 = 2 \\ 10x - 2 - 6x = 2 - 6x \\ 4x - 2 = 2 - 6x \\ 4x + 6x = 2 + 2 \\ 10x = 4 \\ x = \frac{2}{5} [/tex]
I hope this would help
Answer:
Both boys are correct.
Both methods correctly use the properties of equality and inverse operations.
Both methods isolate the variable on one side of the equals sign.
Step-by-step explanation:
das all u need